The method that I use for the Sqaure-1, and is used my many other cubers, is the Lars Vandenburg method. This method is very easy to learn and can be quite fast without learning many algorithms; My personal best average is 23 seconds for a 12 solve average with this method. Below will be the algorithms that I use for solving the Square-1. And this isn't a tutorial, it's just showing you the algorithms that I use for solving the Square-1. *Algorithms in red are the nessicarey algorithms to solve the puzzle with the least amount of algorithms possible.* [To solve the middle bar flip at the end of a solve just use /(6,0)/(6,0)/(6,0) to fix it]

Image Courtesy: Lance Taylor


CO (Corner Orientation): This is the second step in solving the Sqaure-1. In this step you will orient the corners by placing them in their correct layer. Most of the time this step is entirely intuitive so some people may not need these algorithms. The left image is the top layer and the right image is the down layer.

(1,0)/	(0,-1)/(-3,-3)/	(1,0)/(-3,6)/	(1,0)/(0,3)/	(1,0)/(6,6)/

EP (Edge Orientation): This is the third step in solving the Sqaure-1. In this step you will orient the edges by placing them in their correct layer. The left image is the top layer and the right image is the down layer.

(1,0)/(0,-3)/(0,-3)/(-1,-1)/(1,4)/(0,3)/	(0,2)/(0,3)/(1,1)/(-1,-4)/	(1,0)/(-1,-1)/	(1,0)/(0,-3)/(0,-3)/(-1,-1)/(0,3)/(0,3)/	(1,0)/(-1,-1)/(3,3)/(1,1)/

CP (Corner Permutation): This is the fourth step in solving the Sqaure-1. In this step you will permute the corners by placing them in their correct location inside their own respective layer. The left image is the top layer and the right image is the down layer.

/(3,-3)/(-3,0)/(0,3)/(0,-3)/(0,3)/(-3,0)	/(3,-3)/(0,3)/(-3,0)/(3,0)/(-3,0)/(0,3)	/(-3,0)/(3,3)/(0,-3)/	/(3,3)/(3,0) [*3]

/(3,3)/(0,3) [*3]	/(3,-3)/(-3,3)/	/(-3,0)/(3,0) [*2] /	/(0,-3)/(0,3) [*2] /

EP (Edge Permutation): This is the fifth, and final step, in solving the Sqaure-1. In this step you will permute the edges by placing them in their correct location inside their own respective layer. This is by far the longest step in solving the Sqaure-1, but you can do the following algorithms to "2-Look" this step, you would do for the last step in CFOP. As always, the left image is the top layer and the right image is the down layer.

(-2,0)/(3,0)/(-1,-1)/ (-2,1)/(2,0)	(1,0)/(-1,-1)/(6,0)/(1,1)/(5,0)	/(3,-3)/(3,-3)/(0,1)/(-3,3)/ (-3,3)/(-1,0)

(1,0)/ (-1,-1)/(3,0)/(1,1)/ (-3,0)/(-1,-1)/(0,1)	/(3,0)/(1,0)/(0,-3)/ (-1,0)/ (-3,0)/(1,0)/(0,3)/ (-1,0)	(1,0)/(0,-3)/ (-1,0)/(3,0)/(1,0)/(0,3)/(-1,0)/ (-3,0)/

/(3,3)/(1,0)/ (-2,-2)/(2,0)/(2,2)/(-1,0)/ (-3,-3)/(-2,0)/(3,3)/(3,0)/ (-1,-1)/(-3,0)/(1,1)/(-4,-3)	/(-3,0)/(0,3)/ (0,-3)/(0,3)/(2,0)/(0,2)/ (-2,0)/(4,0)/(0,-2)/(0,2)/ (-1,4)/(0,-3)/(0,3)